BR Maths Corner1
Re: BR Maths Corner1
^^^ The PBS Nova special was about Ramanujan.
Nova (1974– )The Man Who Loved Numbers
"The Man Who Loved Only Numbers", as you said, is a biography of the famous mathematician Paul Erdős (by Paul Hoffman. It is written much (IIRC later 1990's. Both books are excellent.
(I can claim/brag a very high Erdős number ) ( Erdős number is the number of "hops" needed to connect the author of a paper with Paul Erdős. An author's Erdős number is 1 if he has coauthored a paper with Erdős, 2 if he has coauthored a paper with someone who has coauthored a paper with Erdős).
(Here is a very famous picture of Erdos with another great mathematician  then 10 year old  Terrence Tao)
Nova (1974– )The Man Who Loved Numbers
"The Man Who Loved Only Numbers", as you said, is a biography of the famous mathematician Paul Erdős (by Paul Hoffman. It is written much (IIRC later 1990's. Both books are excellent.
(I can claim/brag a very high Erdős number ) ( Erdős number is the number of "hops" needed to connect the author of a paper with Paul Erdős. An author's Erdős number is 1 if he has coauthored a paper with Erdős, 2 if he has coauthored a paper with someone who has coauthored a paper with Erdős).
(Here is a very famous picture of Erdos with another great mathematician  then 10 year old  Terrence Tao)
Re: BR Maths Corner1
Amber G., you might know about the "happy ending problem" which was described in the book on Erdos. Let me pose it here.
Given five points in general position in a plane, i.e. no three points form a straight line, prove that there is always a convex quadrilateral.
The problem was given to Erdos and Szekeris by their friend Esther Klien. Both the men scratched their heads until Esther gave the solution.
It was the start of Ramsey Theory program by Erdos and Szekeris.
Erdos gave the problem that name because Szekeris and Esther Klein started a romantic relationship which ended in their marriage.
Given five points in general position in a plane, i.e. no three points form a straight line, prove that there is always a convex quadrilateral.
The problem was given to Erdos and Szekeris by their friend Esther Klien. Both the men scratched their heads until Esther gave the solution.
It was the start of Ramsey Theory program by Erdos and Szekeris.
Erdos gave the problem that name because Szekeris and Esther Klein started a romantic relationship which ended in their marriage.
Re: BR Maths Corner1
Honoring Ramanujan  (And talking about Bhargava etc):
Published today in RMS  Bhargava's class group cube has implications for black hole charges.
This new research published by Renowned Physicist Ashoke Sen and his team.

Ashoke Sen  as I hope most of the people know here as I have mentioned him here in brf, is likely to get Nobel some time  he won the Physics Breakthrough prize and Padma Bushan , (Along with Infosys prize, Dirac Medal, SS Bhatnagar Award, FRS, etc). (Not only that  he did his physics from IIT Kanpur and honored distinguished alum award and is/was prof at MIT )
Published today in RMS  Bhargava's class group cube has implications for black hole charges.
This new research published by Renowned Physicist Ashoke Sen and his team.

Ashoke Sen  as I hope most of the people know here as I have mentioned him here in brf, is likely to get Nobel some time  he won the Physics Breakthrough prize and Padma Bushan , (Along with Infosys prize, Dirac Medal, SS Bhatnagar Award, FRS, etc). (Not only that  he did his physics from IIT Kanpur and honored distinguished alum award and is/was prof at MIT )
Re: BR Maths Corner1
Vayutuvan: I did not know about "happy ending problem" so read about it. Thanks.

There is a very nice article about Dyson, (along with John Conway, Ronald Graham) in New Yorker which I really liked.
The scientists who explored the world with their mind.
Three Mathematicians We Lost in 2020
Dyson, who I had as a prof had major impact on many in the world. As this article says "Freeman Dyson was a translator: he turned physics into math, and those subjects into English for the general public."
Dyson's adviser was Hardy, and he was one of the leading expert on Ramanujan's math. He switched his field from pure math to physics because, as he once said "Math is too messy".. (Story is Harish Chandra  famous Indian Mathematician  once told him that HC decided to switch from Physics to Math because "Physics is too Messy", Dyson told him "He is switching from Math to Physics because of the same reason).
Dyson, according to him, was quite proud of the fact that he (along with Wigner) "discovered" ML Mehta (who was just an obscure student in 50's ) and invited him to Princeton and they worked on Random Matrices, and topics like that (which has come back to fashion now)..and found that spectrum lines of complex nuclei followed math inspired by Ramanujan. (Personally I learned a lot and inspired a lot by these gurus). He was also the bridge between people like Feynman (with his diagrams) and Schwinger (with his rigorous Math) showing that mathematically those methods were equivalent. Dyson will be missed.

There is a very nice article about Dyson, (along with John Conway, Ronald Graham) in New Yorker which I really liked.
The scientists who explored the world with their mind.
Three Mathematicians We Lost in 2020
Dyson, who I had as a prof had major impact on many in the world. As this article says "Freeman Dyson was a translator: he turned physics into math, and those subjects into English for the general public."
Dyson's adviser was Hardy, and he was one of the leading expert on Ramanujan's math. He switched his field from pure math to physics because, as he once said "Math is too messy".. (Story is Harish Chandra  famous Indian Mathematician  once told him that HC decided to switch from Physics to Math because "Physics is too Messy", Dyson told him "He is switching from Math to Physics because of the same reason).
Dyson, according to him, was quite proud of the fact that he (along with Wigner) "discovered" ML Mehta (who was just an obscure student in 50's ) and invited him to Princeton and they worked on Random Matrices, and topics like that (which has come back to fashion now)..and found that spectrum lines of complex nuclei followed math inspired by Ramanujan. (Personally I learned a lot and inspired a lot by these gurus). He was also the bridge between people like Feynman (with his diagrams) and Schwinger (with his rigorous Math) showing that mathematically those methods were equivalent. Dyson will be missed.

 BRF Oldie
 Posts: 9357
 Joined: 31 May 2004 11:31
 Location: The rings around Uranus.
Re: BR Maths Corner1
There are a series of interviews on YouTube with Freeman Dyson talking about Richard Feynman. About math and physics.
I agree Dyson will be missed. Many of us have been missing Feynman for a long time too. He left too early.
I agree Dyson will be missed. Many of us have been missing Feynman for a long time too. He left too early.
Re: BR Maths Corner1
^^^ There is a set of many "oral history" which are my favorites ... (Now they are available on you tube too).
There are a few where he talks about his invitation to Mehta and inviting him to Princeton..
https://www.youtube.com/watch?v=XgPcd1Fz3FA
***
Dyson and Feynman were very good friends  (Both were in Cornell around the same time with Bethe and had lot of adventures there)..One of trip both Feynman and Dyson have talked about a lot (in their auto biography as well as many other sources) was once they travelled across America in car.
(Feynman's famous "Surely you are Joking" talks about quite a few adventures of that journey).
Bethe, Feynman and Dyson  all were extremely quick (even when they were young students) in calculations or guessing/estimating/ complicated integrals etc.
There are a few where he talks about his invitation to Mehta and inviting him to Princeton..
https://www.youtube.com/watch?v=XgPcd1Fz3FA
***
Dyson and Feynman were very good friends  (Both were in Cornell around the same time with Bethe and had lot of adventures there)..One of trip both Feynman and Dyson have talked about a lot (in their auto biography as well as many other sources) was once they travelled across America in car.
(Feynman's famous "Surely you are Joking" talks about quite a few adventures of that journey).
Bethe, Feynman and Dyson  all were extremely quick (even when they were young students) in calculations or guessing/estimating/ complicated integrals etc.
Re: BR Maths Corner1
The thing I know about Hans Bethe is that George Gamow once played a practical joke (which I remember reading either in Gamow's own book, or in somebody else's book when he was talking about Gamow). Apparently Gamow wrote a paper with one Alpher and Hans Bethe. And tried to pass it off as the "Alpher, Bethe, Gamow" paper. And then tried to persuade somebody else to be the fourth author, on condition that the guy changed his last name to "Delter." Paraphrasing, don't remember the exact story.
Hint: Greek alphabet, first four letters.
Hint: Greek alphabet, first four letters.
Re: BR Maths Corner1
^^^ The above story is quite famous .. (I just checked it even has a wiki page  https://en.wikipedia.org/wiki/Alpher%E2%80%93Bethe%E2%80%93Gamow_paper)..
 Ralph Alpher was Gamow's student, and they wrote a famous paper (actually now quite well known about origin of various elements inside stars), and Gamow humorously added Bethe's name (as H Bethe ( (in absentia) and this "alphabetagamma' paper did get published. (Gamow said that since Bethe did not object and was quite helpful in discussions so his name was justified).
The story as you told is interesting as Gamow often joked that a later contributer Herman (who later did computer calculations based on that theory  stubbornly refuses to change his name to Delter.
Anyway  I HIGHLY recommend Gamow's books (he wrote dozens  all best sellers  Many text books but *many* popular books too)  If you can get "Thirty Years That shook Physics" where he has many such stories and interesting history of Physics. ..
I fondly remember visiting University of Colorado (where Gamow settled) had a huge display in their Physics department lobby  all covered with Gamow's published books  Some translated into many languages  I could see Gujrati, Marathi, Hindi etc..)..
 Ralph Alpher was Gamow's student, and they wrote a famous paper (actually now quite well known about origin of various elements inside stars), and Gamow humorously added Bethe's name (as H Bethe ( (in absentia) and this "alphabetagamma' paper did get published. (Gamow said that since Bethe did not object and was quite helpful in discussions so his name was justified).
The story as you told is interesting as Gamow often joked that a later contributer Herman (who later did computer calculations based on that theory  stubbornly refuses to change his name to Delter.
Anyway  I HIGHLY recommend Gamow's books (he wrote dozens  all best sellers  Many text books but *many* popular books too)  If you can get "Thirty Years That shook Physics" where he has many such stories and interesting history of Physics. ..
I fondly remember visiting University of Colorado (where Gamow settled) had a huge display in their Physics department lobby  all covered with Gamow's published books  Some translated into many languages  I could see Gujrati, Marathi, Hindi etc..)..
Re: BR Maths Corner1
Gamow seems to have been quite the clown. I remember a story of his, about some trip (sorry, details are hazy, read a couple of his books long ago) where he and family were going horseriding. Gamow being like 6'3" and pretty big, had a hard time finding a horse to carry him. One was found though, rather ungainly, but bigboned and able to carry his weight. And Gamow promptly named it "Betelgeuse." Betelgeuse (also associated with nakshatra Arudhra) is a gigantic red star in the constellation of Orion, I believe the name is Arabic for "arm of Orion" or "hand of Orion." Gamow OTOH interpreted it as "shoulder of the giant" (the giant being Orion, and Betelgeuse being its left shoulder). He thought the name was appropriate for that horse, since the poor thing had the task of shouldering the giant (i.e., 6'3" Gamow).
Then years later when he visited that same spot, he saw that horse again, and out of curiosity asked one of the guides "what's that horse called?" And the guide replied "Battle Goose, sir." "What? Why Battle Goose?" "I don't know sir, somebody named it that way, and the name just stuck."
Then in one of the math problems in his book, where one had to find the location of a treasure, there was a gallows as a reference point. He used the Greek letter "gamma" as a symbol for the location of that gallows, since the capital Gamma in Greek "even looks like a real gallows." I thought that was pretty creative, his name also being "Gamow."
This seems to be going OT, so I'll stop. It should serve to get folks interested in his books though.
EDIT: Oh, forgot to ask. Is Gamow also the guy who once tried to submit a paper with the title "How to Cook a Helium Nucleus in a Potential Pot"  only to have the editor reject the title? So he was bemoaning the lack of sense of humor in that editor.
Then years later when he visited that same spot, he saw that horse again, and out of curiosity asked one of the guides "what's that horse called?" And the guide replied "Battle Goose, sir." "What? Why Battle Goose?" "I don't know sir, somebody named it that way, and the name just stuck."
Then in one of the math problems in his book, where one had to find the location of a treasure, there was a gallows as a reference point. He used the Greek letter "gamma" as a symbol for the location of that gallows, since the capital Gamma in Greek "even looks like a real gallows." I thought that was pretty creative, his name also being "Gamow."
This seems to be going OT, so I'll stop. It should serve to get folks interested in his books though.
EDIT: Oh, forgot to ask. Is Gamow also the guy who once tried to submit a paper with the title "How to Cook a Helium Nucleus in a Potential Pot"  only to have the editor reject the title? So he was bemoaning the lack of sense of humor in that editor.
Re: BR Maths Corner1
Amber G. wrote:Vayutuvan: I did not know about "happy ending problem" so read about it. Thanks.

There is a very nice article about Dyson, (along with John Conway, Ronald Graham) i
John Conway, one of my favorite mathematicians, succumbed to COVID sometime around MayJune 2020. I forgot to post it here. He was in his mid80s.
Re: BR Maths Corner1
sudarshan wrote:Gamow seems to have been quite the clown.
(Paging @SriKumar, @chillarai, and @Mort Walker as well)
Now you are here, attempt the two problems I posed.
N faced polygon problem and the other is The Happy Ending Problem.
Re: BR Maths Corner1
Vayutuvan wrote:Amber G., you might know about the "happy ending problem" which was described in the book on Erdos. Let me pose it here.
Given five points in general position in a plane, i.e. no three points form a straight line, prove that there is always a convex quadrilateral.
The problem was given to Erdos and Szekeris by their friend Esther Klien. Both the men scratched their heads until Esther gave the solution.
It was the start of Ramsey Theory program by Erdos and Szekeris.
Erdos gave the problem that name because Szekeris and Esther Klein started a romantic relationship which ended in their marriage.
I actually found this one rather easy, don't know if I made some major reasoning error (it's possible). I didn't look it up though, the below are my own thoughts on it.
Eeenh, let's see now (as Bugs Bunny once said)....
Three noncollinear points in a plane will form a triangle, which is always considered convex. When you add a fourth point, which is not collinear with any any of the pairs of previous three points, the quadrilateral formed will be convex if each of the points are outside the triangle formed by the other three. Conversely, if the quadrilateral is concave, then one of the four points will be in the triangle formed by the other three (but not *on* the triangle, since the "no three collinear points" rule precludes that).
So of the five points, select any four. If these four form a convex quad, then the problem is over right there.
So we are concerned with the case where these four don't form a convex quad. Which means, one of them is inside the triangle formed by the other three.
So pick any triangle, and place a point inside it. It is to be shown that if we select a fifth point which is not collinear with any pair out of the previous four, then this fifth point will be such that, at least four out of the five will form a convex quad.
See the figure below. Three of the red dots form a triangle, and the fourth red dot is inside this triangle. The fifth point cannot lie on any of the green or black lines. So the fifth point has to lie within one of the pink, grey, or blue regions.
Last edited by sudarshan on 06 Jan 2021 09:20, edited 1 time in total.
Re: BR Maths Corner1
The important thing to note is, that any of the pink regions are equivalent with any of the other; any of the grey regions are equivalent with any of the other; and any of the blue regions are equivalent with any of the other.
I.e., by flipping or rotating the triangle, whatever is said about the case where the fifth point is in one of the pink/ grey/ blue regions, can be shown to apply to the remaining ones as well.
So simplify the above figure:
I.e., by flipping or rotating the triangle, whatever is said about the case where the fifth point is in one of the pink/ grey/ blue regions, can be shown to apply to the remaining ones as well.
So simplify the above figure:
Re: BR Maths Corner1
Call this fifth point "5." In the above figure, put the fifth point in the pink region. 2, 3, 4, and 5 are guaranteed to form a convex quad (i.e., pick any three of these four points, it will instantly be seen that the fourth is outside the triangle formed by the other three).
Put the fifth point in the grey region, again, 2, 3, 4, and 5 are guaranteed to form a convex quad. (Again  pick any three of these four points, the fourth is instantly seen to be outside the triangle formed by the other three).
Put the fifth point in the blue region. Now, 1, 3, 4, and 5 are guaranteed to form a convex quad (same reasoning as above).
Hence proved. Did I miss anything?
Put the fifth point in the grey region, again, 2, 3, 4, and 5 are guaranteed to form a convex quad. (Again  pick any three of these four points, the fourth is instantly seen to be outside the triangle formed by the other three).
Put the fifth point in the blue region. Now, 1, 3, 4, and 5 are guaranteed to form a convex quad (same reasoning as above).
Hence proved. Did I miss anything?
Re: BR Maths Corner1
If the fifth point is inside the triangle? I will check later unless you show that you already handled that case.
Re: BR Maths Corner1
Vayutuvan wrote:If the fifth point is inside the triangle? I will check later unless you show that you already handled that case.
It's handled already, by this case:
sudarshan wrote:Put the fifth point in the blue region. Now, 1, 3, 4, and 5 are guaranteed to form a convex quad (same reasoning as above).
The blue region is inside the triangle.
Re: BR Maths Corner1
Come listen to acclaimed author Robert Kanigel and renowned mathematician Ken Ono as they discuss The man who knew infinity and representing STEM in literature and cinema! Register now at: https://www.indiasciencefest.org/talks
Re: BR Maths Corner1
Sudarshan and others:
Adding some back ground to "Happy Ending Problem" :
Esther Klein brought this "puzzle" to George Szekeres and Paul Erdős. All were friends/mathematicians in their 20's (in mid 1930's)
"Given five points, and assuming no three fall exactly on a line, prove that it is always possible to form a convex quadrilateral — a foursided shape that’s never indented (meaning that, as you travel around it, you make either all left turns or all right turns)."
This particular problem was not that hard. Esther Klein already knew the solution before she brought it to her friends and her friends were able to prove it for this particular case, but it started all thinking about general case. They were able to prove, for example it needed nine points to guarantee a convex pentagon.
Erdős and Szekeres proposed an exact formula for the number of points it would take to guarantee a convex polygon of any number of sides for n side : (2^(n–2) + 1). But this was a just a conjecture by Erdős  and as he did with many problems, he offered a $500 to anyone who could prove the formula was correct.
The problem is called "Happy Ending" because Esther Klein and George Szekeres fell in love, got married etc.
Erdős passed away in 1996 and Esther & George Szekeres in 2005  Both passed away on the same day within hours of each other. Both were 90+ years old and 70 years have passed  The prize (now managed by others) is still there to be claimed.
From what I know, (have not read the latest)  The only other shape whose result is known is a hexagon, which requires at least 17 points. Some recently published papers by Suk and may be others provides nearly decisive evidence that the intuition that guided Erdős and Szekeres is correct  it has given many interesting tools.
Here is a old picture of the three. (Around 1930) (Photo credit : Ronald Graham (Erdős)/Komal)
Adding some back ground to "Happy Ending Problem" :
Esther Klein brought this "puzzle" to George Szekeres and Paul Erdős. All were friends/mathematicians in their 20's (in mid 1930's)
"Given five points, and assuming no three fall exactly on a line, prove that it is always possible to form a convex quadrilateral — a foursided shape that’s never indented (meaning that, as you travel around it, you make either all left turns or all right turns)."
This particular problem was not that hard. Esther Klein already knew the solution before she brought it to her friends and her friends were able to prove it for this particular case, but it started all thinking about general case. They were able to prove, for example it needed nine points to guarantee a convex pentagon.
Erdős and Szekeres proposed an exact formula for the number of points it would take to guarantee a convex polygon of any number of sides for n side : (2^(n–2) + 1). But this was a just a conjecture by Erdős  and as he did with many problems, he offered a $500 to anyone who could prove the formula was correct.
The problem is called "Happy Ending" because Esther Klein and George Szekeres fell in love, got married etc.
Erdős passed away in 1996 and Esther & George Szekeres in 2005  Both passed away on the same day within hours of each other. Both were 90+ years old and 70 years have passed  The prize (now managed by others) is still there to be claimed.
From what I know, (have not read the latest)  The only other shape whose result is known is a hexagon, which requires at least 17 points. Some recently published papers by Suk and may be others provides nearly decisive evidence that the intuition that guided Erdős and Szekeres is correct  it has given many interesting tools.
Here is a old picture of the three. (Around 1930) (Photo credit : Ronald Graham (Erdős)/Komal)
Re: BR Maths Corner1
Amberji, your statement does not include the coplanar clause which was in Vayutuvan's problem statement. It will be much more difficult to consider non coplanar cases no?
Re: BR Maths Corner1
Najunamar wrote:Amberji, your statement does not include the coplanar clause which was in Vayutuvan's problem statement. It will be much more difficult to consider non coplanar cases no?
Nice to see you here, haven't seen you in this dhaga..
You raise an interesting point. But noncoplanar cases are actually "easier" for 5 points. (or more complex if you want to find general formula)
For example if one generalize this to say 3 dimension, where no four points are on the same plane then 4 points will always form a convex polygon. (Just like in a plane, 3 points will always form a convex polygon). Interestingly here (in 3 dimension) 6 points (where no 4 points are in the same plane) are enough to find 5 points so that when they are cyclic joined will be convex.
In "general" case of the above problem, in k dimension, if one chooses k+3 points, k+2 points can be joined. Erdos conjecture, a modified formula exist. Generally, for every d and k > d there exists a number m(d,k) such that every set of m(d,k) points in general position has a subset of k points that form the vertices of a "neighborly" polytope ..ityadi .. (I do not know a lot  in fact quite little, in graph theory but these problems  even simple looking problems become very hard)

There are some good books ( eg Grünbaum's  Convex Polytopes) and plenty of material but not much in popular books I have seen.
Re: BR Maths Corner1
Amberji thanks!, Yes, I was thinking about > 5 points or a generic octahedron (not regular) in general for just 3D space but as you mentioned could also think of ndimensional space too. Much obliged for the book suggestion  shall search in the public library system.
Re: BR Maths Corner1
Meanwhile on Biden team  as a scientific adviser Eric Steven Lander  MIT professor, mathematician (won medal in IMO). Congratulations.
(Interesting to see, now both in US and India good scientists are getting listened too),
(Interesting to see, now both in US and India good scientists are getting listened too),
Re: BR Maths Corner1
The book by Grunbuam is the authoritative book on Convex Polytopes.
Re: BR Maths Corner1
Congratulations to Adam W. Marcus of EPFL, Daniel Alan Spielman of Yale University, and Nikhil Srivastava of University of California, Berkeley, winners of the 2021 National Academy of Sciences’ Michael and Sheila Held Prize for their work on the KadisonSinger problem and Ramanujan graphs! (It's a $100,000 prize)
Re: BR Maths Corner1
Sad to hear Hank Aaron's passed away today.
He leaves his mark in Mathematics too! In mathematics, a Ruth–Aaron pair consists of two consecutive integers (e.g., 714 and 715) for which the sums of the prime factors of each integer are equal:
714 = 2 × 3 × 7 × 17,715 = 5 × 11 × 13,
and
2 + 3 + 7 + 17 = 5 + 11 + 13 = 29.
(Aaron's 715th home run broke Ruth's 714 record).
(A Famous theorem by renowned mathematicians Erdos and Pomerance proves that such pairs are extremely rare (have density 0 )
Famous joke is that Hank Aaaron's Erodos number is 1! (Hank Aaron has an Erdős number of 1 because they both autographed the same baseball when Emory University awarded them honorary degrees on the same day.)
Rest in peace!
(Pictured below: Two legends Paul Erdos with Hank Aaron)
(You may like this: https://youtu.be/aCq04N9it8U)
He leaves his mark in Mathematics too! In mathematics, a Ruth–Aaron pair consists of two consecutive integers (e.g., 714 and 715) for which the sums of the prime factors of each integer are equal:
714 = 2 × 3 × 7 × 17,715 = 5 × 11 × 13,
and
2 + 3 + 7 + 17 = 5 + 11 + 13 = 29.
(Aaron's 715th home run broke Ruth's 714 record).
(A Famous theorem by renowned mathematicians Erdos and Pomerance proves that such pairs are extremely rare (have density 0 )
Famous joke is that Hank Aaaron's Erodos number is 1! (Hank Aaron has an Erdős number of 1 because they both autographed the same baseball when Emory University awarded them honorary degrees on the same day.)
Rest in peace!
(Pictured below: Two legends Paul Erdos with Hank Aaron)
(You may like this: https://youtu.be/aCq04N9it8U)
Re: BR Maths Corner1
sudarshan wrote:The important thing to note is, that any of the pink regions are equivalent with any of the other; any of the grey regions are equivalent with any of the other; and any of the blue regions are equivalent with any of the other.
I.e., by flipping or rotating the triangle, whatever is said about the case where the fifth point is in one of the pink/ grey/ blue regions, can be shown to apply to the remaining ones as well.
So simplify the above figure:
[img...]https://live.staticflickr.com/65535/50805626806_e6309dabe6_c.jpg[/img]
Nice figure. I think you are looking at the convex cones. Probably that will show a way to work on higher dimensional variations of the problem. I was reading something else and came up on the problem and read the solution. It is simpler than you think. It is through case analysis as follows.
Case 1: Convex hull contains all 5 points. Then any four points will form the required convex quad.
Case 2: Convex hull contains 4 points. That is the required convex quad.
Case 3: Convex hull contains 3 points, ie, a triangle. That means two points are inside the triangle. The line defined by these two interior points divides the triangle into two parts  one part contains one vertex of the triangle and the other two vertices. These vertices and the two internal vertices form the required convex quad.
Re: BR Maths Corner1
Najunamar wrote:Amberji, your statement does not include the coplanar clause which was in Vayutuvan's problem statement. It will be much more difficult to consider non coplanar cases no?
You are a Geometer or algebraist? Computational? Linear programming?
Re: BR Maths Corner1
https://slashdot.org/story/21/03/08/0344224/furiousairesearchercreatessiteshamingnonreproduciblemachinelearningpapers
The state of AI/ML research is much worse than I previously thought. Not all that surprising considering the amount of "venture capital" flowing into this rabbit hole.
"Easier to compile a list of reproducible ones...," one user responded.
"Probably 50%75% of all papers are unreproducible. It's sad, but it's true," another user wrote. "Think about it, most papers are 'optimized' to get into a conference. More often than not the authors know that a paper they're trying to get into a conference isn't very good! So they don't have to worry about reproducibility because nobody will try to reproduce them." A few other users posted links to machine learning papers they had failed to implement and voiced their frustration with code implementation not being a requirement in ML conferences.
The next day, ContributionSecure14 created "Papers Without Code," a website that aims to create a centralized list of machine learning papers that are not implementable...
Papers Without Code includes a submission page, where researchers can submit unreproducible machine learning papers along with the details of their efforts, such as how much time they spent trying to reproduce the results... If the authors do not reply in a timely fashion, the paper will be added to the list of unreproducible machine learning papers
The state of AI/ML research is much worse than I previously thought. Not all that surprising considering the amount of "venture capital" flowing into this rabbit hole.
Re: BR Maths Corner1
Allow me to share a picture from a playground near Ramanujan's birthplace ( Kumbakonam, India). Photo was taken around 2005. Swinging away are world renowned mathematicians  and experts on Ramanujan's work.
Prof. Manjul Bhargava (Padmbhushan, India's first field medalist, winner of SHASTRA Ramanujan Prize and many other prestigious awards),
Prof. Krishnaswami Alladi.
Prof Ken Ono
and Prof Mira Bhargava (Manjul's mom) (A excellent mathematician in her own right)
(Photo credit : Prof Ken Ono)
(People in Brf may be familiar with these mathematicians as I have mentioned them several times. Prof. Bhargava and Prof Ono were technical advisers for the famous movie "Man who knew Infinity" and have been involved in many other documentaries and books about Ramanujan's life and Math)
Prof. Manjul Bhargava (Padmbhushan, India's first field medalist, winner of SHASTRA Ramanujan Prize and many other prestigious awards),
Prof. Krishnaswami Alladi.
Prof Ken Ono
and Prof Mira Bhargava (Manjul's mom) (A excellent mathematician in her own right)
(Photo credit : Prof Ken Ono)
(People in Brf may be familiar with these mathematicians as I have mentioned them several times. Prof. Bhargava and Prof Ono were technical advisers for the famous movie "Man who knew Infinity" and have been involved in many other documentaries and books about Ramanujan's life and Math)
Re: BR Maths Corner1
sudarshan wrote:Amber G ji, maybe you could suggest to Dr. Vidyasagar et al, that the bijaganita (tr.: algebraic; literally: "seed mathematics") terms in that supermodel could use Sanskrit aksharas instead of Greek letters. There's more than enough letters in Indian languages, and after all, the concept of bijaganita did originate in India.
The Model is now called SUTRA .
Re: BR Maths Corner1
Hours/days/weeks/months/years of fun (depending on how sharp your mathematical mind is).
For me it would be years if not decades :(
American Mathematical Monthly Problems  2021
For me it would be years if not decades :(
American Mathematical Monthly Problems  2021
The American Mathematical Monthly is an expository journal intended for a wide audience of mathematicians, from undergraduate students to research professionals. Each issue has a Problems and Solutions section where several new problems are proposed. Below you can find the solutions that I've submitted this year (pdfs will be available after the deadline). As regards the previous years, you can take a look through the following links (but beware of nerd sniping ): 2020 (45), 2019 (41), 2018 (36), 2017 (40), 2016 (50), 2015 (48), 2014 (41), 2013 (29), 2012 (22), 2011 (22), 2010 (15), 2009 (13), 2008 (16), 2007 (15), 2006 (16), 2005 (22), 2004 (13), 2003 (13), 2002 (6), 20011993 (19).
For anyone who is interested in sharing hints and solutions, please feel free to contact me at ...
Return to “Technology & Economic Forum”
Who is online
Users browsing this forum: No registered users and 35 guests