Fellow BRF members:

I am probably the only brf oldie, for whom, Math dhaga comes as one of the most active dhaga. Thanks to Ramana who started this thread. I too, kind of took a lead here and posted many problems, commented on Maths recent issues, posted math related news items etc. In all I enjoyed (and continue to enjoy) posting and reading this thread. From the feed back we got, I think similar views are shared by many.

Yet, I have to be honest. I don't know in which direction BRF is going. Personally I don't know if I can even continue posting here , even if I want to, as powers to be here, it seems to me, are clearly telling me that BRF is no longer a place for diverse views or technical discussion.

Of course, I am not the first, or will be last, who has articulated this. Many of valuable contributors, at least it seems to me, have articulated this.

To underscore that I am not overreacting, let me just point out one example, in this Math dhaga itself.

One of the moderator gave me a board warning (my first board warning!) for my comments in math thread, and called my comment “idiocy”. He rebuked me as someone “who wanted to test math ability in nuke discussion thread” :?

See:

this for detailsPlease also see my reply to that:

(Reply) What is noteworthy to me is

1- No admin ever (in last 3 years) made a comment about uncivil language used against me. (pointed out in my reply above)

2. Many of the other members, including admins, who since then made no contribution to math thread, jumped in to pass a few more insults.

3. Even after 3 years, no one has answered or gave clarification to the question I raised, namely, how the original problem/observation posed there made sense or why some seemingly random, and sometimes broken links given there, were relevant?

I do not think I am over reacting . I have tried to give honest feed back to forum admins with little result. Others are free to give feedback to BRF admins.

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Let me end this with a less known but a beautiful theorem in Geometry.

Take any triangle, trisect each angle. The inner triangle thus formed (try to draw it and you will know what I mean) will always be a equilateral triangle. (If outer triangle is ABC, and inner PQR while angles

CBP = PBR = RBA , and angles BAR=RAQ=QAC and angles ACQ=QCP=PCB – triangle PQR will always be a equilateral triangle no matter what shape is ABC)