Jayram wrote:This from ISRO page
"We've the signal. 1099 m/s. Expected - 1098.7 m/s"
What is this? And why is it important.. how does this relate to MOM insertion? Some gyan please thanks..
An error of ~ 1.0e-4. Somebody please say that this is good enough. Otherwise the orbit might start spurring inward. May be one more small burn is required later on at an opportune moment.
Matrimc - Knowing your math background I am little surprised that you did not answer your own question..
.(Short answer - don't worry --- much better than we hoped)
(Change in orbit is really insignificant)
Any way equation posted by Bade (or me) many moons ago, here in this thread..v = sqrt(k ( 2/r - 1/a))
is all you need.
(It is a simple and very useful equation for all others too
Here v = velocity of MOM in meter/s (Should be around 4000 m/s around the perigee)
k = 4.283 * 10 ^13 for Mars (see my earlier post)
r = distance from center of Mars to MOM (in meters) - remember Mars, radius is 3397 Km, so that has to be taken into account (It will vary from 4500 Km and 80000 Km -- period of 3 days)
a=semi- major axis (1/2 the distance between minimum and maximum distance in the orbit -- about 40,000 Km)
So you see , even if error in delta-V was 10x than .3 (say a few meters/sec) the mission in all respect would have been a very successful mission.
As to remaining fuel, even if we were left with a few Kg, IMO, it would have been sufficient to keep the MOM in orbit for months.. (fuel now is needed only for things like minor adjustments... (say if we want to take a closer look at one of the moons).. orienting the antena etc..).. As I said in my earlier post (before MOI), estimates if all goes well, was to be left with 40-50 Kg of fuel (we are left with about 45 kg)..