Re: Physics Thread.
Posted: 25 Apr 2015 06:23
It is c.sanjaykumar wrote:What is the speed of light for an observer travelling in a frame of reference relative to the photon at c ?
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It is c.sanjaykumar wrote:What is the speed of light for an observer travelling in a frame of reference relative to the photon at c ?
Hi, you may already know that, but I did post (in 2009) about PKI ("father of India's cold fusion")'s video about cold fusion and "mega-gauss-bombs"...
Yes, Good math background is needed..(I say physics is math with purposevayu tuvan wrote:I would say in addition to physics courses, some applied mathematics will be very helpful. Then one doesn't have to depend on "descriptive" physics.
Seems like the object has 2 points of equilibrium both unstable, and is alternating between the two due to lack of gravitational resistance in space and any sources of dissipation.Ankar wrote:Unstable spin in Zero-Gravity
To add - this and similar problems, at least to me, are fairly well known -- I have heard it many times in serious discussion. Feynman was known, for example, throwing spinning food trays up in the air, and asking one to explain the "flipping". (he claimed that thinking about math part of these is what inspired him to do noble-prize winning type serious physics)SriKumar wrote:Cross-posting 'ankar's' post to here. An object (a space 'spanner'?) flipping between two states of unstable (?) equilibrium.
Seems like the object has 2 points of equilibrium both unstable, and is alternating between the two due to lack of gravitational resistance in space and any sources of dissipation.Ankar wrote:Unstable spin in Zero-Gravity
Just a comment - one will see the same kind of rotary motion on earth (except that the object will be failing down so the flip may be hard to observe).. as the above video shows. Since in space, things do not fall down, one has a longer time to observe....due to lack of gravitational resistance in space and any sources of dissipation.
SriKumar - I think you are right that throwing books (or lunch boxes) up in the air may have been much more common, but many would not notice/think about this strange phenomena unless pointed out (at least I did not). Funny thing is, it is NOT the longest or the shortest side (as one would intuitively may find reasons for) but the middle side where , even with good practice, it is almost impossible to keep the rotation stable.SriKumar wrote:You are welcome. Actually I posted it here for a discussion/explanation...so thanks for that.
It is funny but the 'book flipping' test was something a middle-school classmate of mine mentioned to me...when he was trying to flip his lunch box (a cubiod shape). Since then, I've flipped a lot of books ......with no new enlightenment dawning on me. The exercise in space is still quite interesting because the book (space spanner) stays in the 'air' long enough to show it reverse the direction of its flipping, which one cannot see it at earth because the book 'lands' quickly.
Question: If there was dissipation in the system to bleed out energy from the rotating object e.g. due to air, or better yet, if it were done in water; how would the motion change over time? Would it 'finally settle' into a state of stable equilibrium (as assuming there is one, between the 2 unstable states) or would it continue to alternate between the 2 unstable states but with a lower 'amplitude' i.e. it does not swing far enough? Or does the rpm slow down but it continues to hit the points of unstable equilibrium? I am guessing it is the last option.
If I have to describe it, it is really not "swinging" between 2 points - nothing like a pendulum, or regular swing etc..every point (as far angular velocity in a given direction is concerned) there is instability all the time except that there are two points where there is equilibrium which is unstable. IOW it is very hard (without using computer -numerical methods, in practice) to describe/predict the motion except to say it is something like "unpredictable". (It is like, one can easily "study" collision of two particles (their momentum/energy before and after the collision - but it is very hard to calculate what the shape of a car will be after an accident)..(The particular video you posted, there does seem some sort of regular motion (may be due to particular shape of the object), but see some of the other videos, or do the experiment, all one can say is that the tumble is irregular)So it seems like the rotating object (book/box/space spanner) swings through 2 points of unstable equilibrium.
Loss of energy etc has no importance here. Loss of energy or angular momentum is not relevant here. (Sure, if done under water, motion will slow down, as one thinks but that is hardly the point here). IOW the energy or angular momentum can be considered CONSTANT (negligible loss to air etc). Similarly practically speaking, gravity (or lack of it) plays NO part. (Gravity introduces NO torque and hence produces no changes in the rotation).If there was dissipation in the system to bleed out energy from the rotating object e.g. due to air, or better yet, if it were done in water; how would the motion change over time?
Hello Vayu tuvan -vayu tuvan wrote:My guess is that microgravity is the one of the keys, so are the starting conditions and the non-existence of a perfectly symmetric physically realizable body.
If there is no gravity at all - is there any place in the universe which does not have 0 gravitational field? - and the object is rotated such that the rotational axis is aligned with the axis of symmetry perfectly and there are no imperfections in the object, there are no flips.
The "difference" here is simply moment of Inertia which is different, depending on the axis.Same way, if a top made out of a disk and and a round stick going through the centre of the disk is spun on the ground, no distinction can be made between the handle and the tip.
I think many people may not even know what is a Hamiltonian
Broadly speaking, the Hamiltonian is (double? I have to think more about this) saddle shaped. That is the connection to JVM and Morgenstern's game theory.
We live in 3-dim space and the 3 eigenvalues we mean are of Inertia matrix(tensor).vayu tuvan wrote:Another question:
Let us assume that I have a system of point masses connected by mass less rigid rods such that these point masses are all in fixed position with each other. Then we rotate this point mass assembly around an axis that goes through its center of {mass, gravity, momentum} (I am not sure which one to chose here). How many stable and unstable equillibria this assembly has?
AmberG: Why are there only three eigenvalues? T
Except that this matrix is symmetric so.. Eigen values are always real...! (As one will guess for this kind of real system)vayu tuvan wrote:I was reading up a little also. For a 3x3 matrix, if you have one real eigenvalue and a complex conjugate pair with the real part opposite in sign of the real eigen value, then there the complex pair makes the two unstable equilobrium configurations.
gakakkad wrote:http://agnitantra.com/battery/
evidently ancient India had knowledge about electricity and also rudimentary electrochemistry
the sage agastya had made dry cell...
the dark ages coincided with the abrahamic religions expansion... One surely needs to ponder how much Indians knew and how far had our great saints had reached in science ... gravity , calculus and astronomy were well known..they had concepts of atoms and photons ...
why did we not transition into an Industrial society back in 1000 AD is a mystery our historians should explore...
AmberG: Yes, I realize the importance of symmetry. If it is positive (negative) definite, all eigenvalues are real and positive (negative). In that case, there is only one global minimum (maximum).Amber G. wrote:Except that this matrix is symmetric so.. Eigen values are always real...! (As one will guess for this kind of real system)vayu tuvan wrote:I was reading up a little also. For a 3x3 matrix, if you have one real eigenvalue and a complex conjugate pair with the real part opposite in sign of the real eigen value, then there the complex pair makes the two unstable equilobrium configurations.
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Yes the matrix is positive definite symmetric (can be proven) and so, as expected, all values are real and positive..vayu tuvan wrote:AmberG: Yes, I realize the importance of symmetry. If it is positive (negative) definite, all eigenvalues are real and positive (negative). In that case, there is only one global minimum (maximum).Amber G. wrote:
Except that this matrix is symmetric so.. Eigen values are always real...! (As one will guess for this kind of real system)
I commented on this before (see previous posts). The interesting case is when 3 moment of inertia's are different , and the spinning axis happens to align with the intermediate principle axis.I have one more question - how come Earth or moon do not flip? Is it because the axis is perfectly aligned due to construction (i..e the formation process of earth and moon etc.)?
If that were to be the case, there is only minimum whichn by definition is the [global] minimum. I am thinking that you cannot have +ve definiteness for this 3x3 matrix.Yes the matrix is positive definite symmetric (can be proven) and so, as expected, all values are real and positive..
..I am assuming a sliding mass (i.e. no car, no wheels, no friction, no rolling anything...just two masses sliding down an inclined plane).
Couple of things....my above eqn. should be m*g*sin(theta) and not cos(theta) for the pulling force (the _reaction_ force is m*g*cos(theta))....been a while since I did this.Amber G. wrote:^^^Good analysis. Let us see if there are more comments/discussion specially interesting will be to see people (those who have not heard of the problems before) doing (or watching) actual experiments and seeing if their guesses/calculations were correct..
(Next best thing is searching/googleing and seeing the demo on a you-tube, )
For example:..I am assuming a sliding mass (i.e. no car, no wheels, no friction, no rolling anything...just two masses sliding down an inclined plane).
...But in real life we do have cars with wheels and frictionSo, in practice will that matter significantly or will have negligible effect?..
No it doesn't. the whole premise of Einsteins work was the constancy of the speed of light in all directions for a given observer.sanjaykumar wrote:So the observer travelling alongside the photon, at c, will see it travelling at c? Or will he now see a photon at rest mass. If the photon really (whatever that means) has rest mass 0, will it disappear?
So Einstein's theory of relativity is seemingly incomplete just as was Newton's.